Question

A metal loses -345 J of heat when going from 75.1 °C to 25.8 °C. If the metal has a mass of 17.4 g, what is the specific heat of the metal?​

Answer 1

We can use the formula:

q = mcΔT

where q is the heat lost, m is the mass of the metal, c is the specific heat, and ΔT is the change in temperature.

Plugging in the values we get:

-345 J = (0.0174 kg) c (75.1 °C - 25.8 °C)

Simplifying and solving for c, we get:

c = -345 J / (0.0174 kg * 49.3 °C)

c = -345 J / 0.85602 J/kg °C

c = 403 J/kg °C

Therefore, the specific heat of the metal is 403 J/kg °C.

Step-by-step explanation:

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