Answer:
The balanced chemical equation for the neutralization reaction between sulfuric acid (H2SO4) and potassium hydroxide (KOH) is:
H2SO4 + 2KOH → K2SO4 + 2H2O
To determine the maximum amount of K2SO4 that can be produced, we need to determine the limiting reactant in the reaction. This is the reactant that will be completely consumed, limiting the amount of product that can be formed.
First, let's calculate the amount of sulfuric acid and potassium hydroxide present in the reaction:
Amount of H2SO4 = volume × concentration = 0.650 L × 0.480 mol/L = 0.312 mol
Amount of KOH = volume × concentration = 0.600 L × 0.250 mol/L = 0.150 mol
According to the balanced equation, 1 mole of H2SO4 reacts with 2 moles of KOH to produce 1 mole of K2SO4. Therefore, the amount of K2SO4 that can be produced is limited by the amount of KOH present:
Amount of K2SO4 = 0.150 mol × (1 mol K2SO4/2 mol KOH) = 0.075 mol
To determine the concentration of sulfuric acid remaining after the reaction, we need to calculate the amount of sulfuric acid that reacted with the KOH:
Amount of H2SO4 reacted = 0.150 mol × (1 mol H2SO4/2 mol KOH) = 0.075 mol
The amount of sulfuric acid remaining is the initial amount minus the amount that reacted:
Amount of H2SO4 remaining = 0.312 mol - 0.075 mol = 0.237 mol
To calculate the concentration of sulfuric acid remaining, we divide the amount by the final volume, which is the sum of the initial volumes of the two solutions:
Final volume = 0.650 L + 0.600 L = 1.25 L
Concentration of H2SO4 remaining = 0.237 mol/1.25 L = 0.190 M
Therefore, the maximum amount of K2SO4 that can be produced is 0.075 mol, and the concentration of sulfuric acid remaining after the neutralization reaction is complete is 0.190 M.
Step-by-step explanation:
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