Question

15. And 17. Find the value of the trigonometric ratio. And the degree of the angle. Show work!

Answer 1

see explanation

Explanation:

15

tan C =
`(opposite)/(adjacent)` =
`(AB)/(BC)` =
`(12)/(35)` , then

∠ C =
`tan^(-1)` (
`(12)/(35)` ) ≈ 18.9° ( to the nearest tenth )

17

sin Z =
`(opposite)/(hypotenuse)` =
`(XY)/(XZ)` =
`(12)/(37)` , then

∠ Z =
`sin^(-1)` (
`(12)/(37)` ) ≈ 18.9° ( to the nearest tenth )