Answer:
To find the initial speed of the frog, we can use the equation for the maximum height reached in projectile motion:
Maximum height = (initial velocity^2 * sin^2(theta))/2g
Where:
- `initial velocity` is the speed at which the frog jumped
- `theta` is the angle at which the frog jumped (assuming it's a simple vertical jump, `theta` would be 90 degrees)
- `g` is the acceleration due to gravity (9.8 m/s^2)
Plugging in the known values, we get:
1 = (initial velocity^2 * sin^2(90))/2(9.8)
Simplifying and solving for `initial velocity`, we get:
initial velocity = √(2gh) = √(2 * 9.8 * 1) = 4.43 m/s
Therefore, the frog's initial speed was 4.43 m/s.