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|x+1| + |x-2| = 3 i need help with this pls

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User Smora
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1 Answer

2 votes

Answer:

-1 ≤ x ≤ 2

Explanation:

You want the solution to |x +1| +|x -2| = 3.

Graph

We find it convenient to solve these absolute value equations using a graphing calculator. When we subtract 3 from both sides, we have ...

|x +1| +|x -2| -3 = 0

The solutions will show on the graph as places where the expression has a value of 0, that is, the x-intercepts.

The left-side expression has a value of 0 for all values of x between -1 and +2, inclusive. That is, the solution is ...

-1 ≤ x ≤ 2

Algebra

The absolute value function is piecewise defined:

|x| = x . . . . for x ≥ 0

|x| = -x . . . . for x < 0

That is, the behavior of the function changes at x=0.

In the given equation the absolute value function arguments are zero at ...

x +1 = 0 ⇒ x = -1

x -2 = 0 ⇒ x = 2

These x-values divide the domain of the equation into three parts.

x < -1

In this domain, both arguments are negative, so the equation is actually ...

-(x +1) -(x -2) = 3

-2x +1 = 3

-2x = 2

x = -1 . . . . . . not in the domain

-1 ≤ x < 2

In this domain, the argument (x+1) is positive, but the argument (x-2) is negative. That means the equation is ...

(x +1) -(x -2) = 3

1 +2 = 3

True for all x in this domain.

x ≤ 2

In this domain, both arguments are positive, so the equation is ...

(x +1) +(x -2) = 3

2x -1 = 3

2x = 4

x = 2 . . . . in the domain (this point was excluded from x < 2).

The solution is -1 ≤ x ≤ 2.

|x+1| + |x-2| = 3 i need help with this pls-example-1
answered
User Josh Stone
by
8.3k points

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