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How many milliliters of 11.5 M HCl(aq) are needed to prepare 585.0 mL of 1.00 M HCl(aq)?
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How many milliliters of 11.5 M HCl(aq) are needed to prepare 585.0 mL of 1.00 M HCl(aq)?
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Jan 28, 2024
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How many milliliters of 11.5 M HCl(aq) are needed to prepare 585.0 mL of 1.00 M HCl(aq)?
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Espen Burud
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Answer:
72.174mL
Explanation:
M1V1=M2V2
V1=M2V2 over M1=
830 × 1 over 11.5 = 72.174mL
Sneep
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Feb 1, 2024
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Sneep
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