Question

MZADB
121° C
B
PLEASE HELP!

Answer 1

Check the picture below.

now, we're making an assumption that DA and DB are both tangential to the circle, and therefore, the point of tangency is always a right-angle, so for this quadrilateral

`\underset{in~degrees}{\textit{sum of all interior angles}}\\\\ S = 180(n-2) ~~ \begin{cases} n=\stackrel{number~of}{sides}\\[-0.5em] \hrulefill\\ n=4 \end{cases}\implies S=180(4-2)\implies S=360 \\\\[-0.35em] ~\dotfill\\\\ \measuredangle ADB+90+121+90=360\implies \measuredangle ADB+301=360\implies \measuredangle ADB=59^o`