The amount of energy required to freeze a substance is known as the heat of fusion, which for water is 334 J/g. This means that 334 Joules of energy are required to freeze one gram of water.To find out how much energy is needed to freeze a 12.3 gram sample of water, we can multiply the mass by the heat of fusion:Energy = mass x heat of fusion
Energy = 12.3 g x 334 J/g
Energy = 4,110.2 JTherefore, 4,110.2 Joules of energy must be removed from the system to freeze a 12.3 gram sample of water.