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Humid air at 100 psia and 400°F and a humidity ratio of 0.024 lbm H2O/lbm dry air is expanded to 15 psia in an isentropic nozzle. How much of the initial water vapor has been converted to liquid water at the nozzle outlet? The specific heat ratio of air at room temperature is k = 1.4. Use data from the tables.

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User Fivebob
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Final answer:

To determine the amount of water vapor converted to liquid in the nozzle, one would need to conduct a thermodynamic analysis using the initial and final conditions of the air, along with psychrometric data. The mass of liquid water formed can then be calculated by a mass balance comparison before and after expansion.

Step-by-step explanation:

Calculating Water Vapor Conversion to Liquid Water

The question relates to the isentropic expansion of humid air in a nozzle from 100 psia to 15 psia and the amount of water vapor that condenses to liquid water during this process. Using the given humidity ratio, the expansion can be analyzed using principles of thermodynamics and the psychrometric chart. However, the complete analysis requires specific tables and data that are not provided in the question. The specific heat ratio k = 1.4 for air is helpful for gas expansion calculations, but additional data like the saturation properties of water at various temperatures and pressures are also needed.

It is noteworthy that the actual calculation for liquid water formation would involve determining the final temperature and the humidity ratio at the nozzle outlet, then applying mass balance for the water content before and after the expansion. If final conditions are below the saturation temperature at 15 psia, some water vapor would have condensed. The difference between the initial water vapor content and the final vapor content (considering any liquid formed) will reveal the mass of condensed water. This requires extensive use of thermodynamic tables or software.

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User Hlynbech
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