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The path of motion of a 8-lb particle in the horizontal plane is described in terms of polar coordinates as r = (2 t + 1)ftand θ = (0.2 t2 − t) rad, where t is in seconds

Part A
Determine the magnitude of the unbalanced force acting on the particle when t = 3 s .

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User Ilce
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1 Answer

6 votes

Answer:

r=(2(2)+1)=5

the magnitude is 5

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User Altonymous
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