Question

The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room. Which equations can be used to solve for y, the length of the room? Select three options. y(y + 5) = 750 y2 – 5y = 750 750 – y(y – 5) = 0 y(y – 5) + 750 = 0 (y + 25)(y – 30) = 0

Answer 1

B, C, E

Explanation:

For a rectangle,

area = length × width

Let length = y.

Then the width is y - 5.

A = LW

750 = y(y - 5)

y(y - 5) = 750

y² - 5y - 750 = 0

All equations that can be put in the form above are correct.

A) y(y + 5) = 750

y² + 5y - 750 = 0

No

B) y² – 5y = 750

y² - 5y - 750 = 0

Yes

C) 750 – y(y – 5) = 0

750 - y² + 5y = 0

y²- 5y - 750 = 0

Yes

D) y(y – 5) + 750 = 0

y² - 5y + 750 = 0

No

E) (y + 25)(y – 30) = 0

y² + 25y - 30y - 750 = 0

y² - 5y - 750 = 0

Yes