Question

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what’s the partial pressure of argon in a mixed gas containing 0.522 atm of He, 322 mm Hg of Ne, and argon if the total pressure is 187 kPa

Answer 1

the partial pressure of argon in the mixture is 91.2 kPa.

Step-by-step explanation:

To find the partial pressure of argon, we need to first calculate the total pressure contributed by the other gases in the mixture:

Total pressure = Partial pressure of He + Partial pressure of Ne + Partial pressure of Ar

We can convert the pressure of He and Ne into units of kPa to match the units of the total pressure:

Partial pressure of He = 0.522 atm x 101.325 kPa/atm = 52.9 kPa

Partial pressure of Ne = 322 mmHg x 1 kPa/7.5006 mmHg = 42.9 kPa

Substituting these values and the given total pressure into the equation above, we can solve for the partial pressure of Ar:

187 kPa = 52.9 kPa + 42.9 kPa + Partial pressure of Ar

Partial pressure of Ar = 187 kPa - 52.9 kPa - 42.9 kPa

Partial pressure of Ar = 91.2 kPa

Therefore, the partial pressure of argon in the mixture is 91.2 kPa.