Answer: $1.69
Explanation:
To find Lenaert's expected gain, we need to calculate the average value of a single bill if he selects and keeps one bill from the bag.
First, let's calculate the total value of all the bills in the bag:
3 x $1 = $3
5 x $5 = $25
6 x $10 = $60
1 x $20 = $20
Total value = $3 + $25 + $60 + $20 = $108
Now, let's calculate the probability of selecting each type of bill:
Probability of selecting a $1 bill = 3/15 = 0.2
Probability of selecting a $5 bill = 5/15 = 0.33
Probability of selecting a $10 bill = 6/15 = 0.4
Probability of selecting a $20 bill = 1/15 = 0.067
Finally, we can calculate the expected value of a single bill with the formula:
Expected value = (probability of selecting a bill) x (value of the bill)
So Lenaert's expected gain if he selects and keeps one bill from the bag is:
(0.2 x $1) + (0.33 x $5) + (0.4 x $10) + (0.067 x $20) = $1.69
Therefore, Lenaert can expect to gain an average of $1.69 if he selects and keeps one bill from the bag.