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Write the equation of the line perpendicular to y=-1/3x+5 and passes through the point (1,-10)

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Answer:

Explanation:

First, we need to determine the slope of the line we want to find since it is perpendicular to the given line. The slope of a line perpendicular to another line is the negative reciprocal of the slope of the given line.

The given line has a slope of -1/3, so the slope of the line we want to find is 3 (the negative reciprocal of -1/3).

Now we can use the point-slope form of the equation of a line to find the equation of the line passing through (1,-10) with a slope of 3:

y - y1 = m(x - x1)

where m is the slope and (x1, y1) is the point. Substituting the values we have:

y - (-10) = 3(x - 1)

Simplifying:

y + 10 = 3x - 3

Subtracting 10 from both sides:

y = 3x - 13

Therefore, the equation of the line perpendicular to y=-1/3x+5 and passing through the point (1,-10) is y = 3x - 13.

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