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Determine the equation of the circle with center (6,-2)containing the point (14,6).

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Answer:

(x -6)² +(y +2)² = 128

Explanation:

You want the equation of the circle centered at (6, -2) through point (14, 6).

Circle equation

The equation of a circle with center (h, k) and radius r is ...

(x -h)² +(y -k)² = r²

For center (h, k) = (6, -2), we can find the value of r² knowing that it will be the value that lets the point (14, 6) satisfy the equation.

(14 -6)² +(6 -(-2))² = r² = 8² +8² = 128

The circle equation is ...

(x -6)² +(y +2)² = 128

Determine the equation of the circle with center (6,-2)containing the point (14,6).-example-1
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User Bogdan Dincescu
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