Question

The formula v= √√2gh gives the velocity v, in feet per second, of an object after it falls h feet accelerated by gravity g, in feet

per second squared. If g is approximately 32 feet per second squared, find how far an object has fallen if its velocity is 96 feet
per second.

Answer 1

We can rearrange the formula to solve for h:

v = √√2gh

Squaring both sides: v^2 = 2gh

Dividing both sides by 2g: h = v^2 / 2g

Substituting v = 96 ft/s and g = 32 ft/s^2, we get:

h = (96 ft/s)^2 / (2 × 32 ft/s^2)

h = 288 ft

Therefore, the object has fallen 288 feet.