Answer: x=a/3 x=a/5
Explanation:
15x²-2ax = a² subtract a² from both sides
15x²- 2ax - a² = 0
You would solve this like you would any quadratic. Factor.
Start my multiplying the first and last coefficients
15(-a²) = -15a² =>find 2 numbers that multiply to this but add to middle
term (-2a)
-5a and +3a multiply to -15a² and adds to -2a
Substitute the middle term with the numbers we just found, keeping the x
15x²- 2ax - a² = 0
15x²- 5ax+3ax - a² = 0 > group the first 2 terms and last 2
(15x²- 5ax)(+3ax - a²)= 0 > this is not your factors, you need to take
GCF out of each grouping
5x(3x-a)+a(3x-a)=0 >if the parenthesis is same, you did good
now the parenthesis is your GCF and one of
your factors, whatever is left is your other
factor
(3x-a)(5x-a)=0 > set each factor = 0 and solve for x
(3x-a)=0 and (5x-a)=0
x=a/3 x=a/5