Question

5.1 g sodium carbonate solution was dissolved in water to make 500cm³ of solution.20cm³ of this solution was tirated against 20.45 cm³ of 0.04M hydrochloric acid . Calculate the % of purity of the sodium carbonate solid

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Answer 1

We know that, Va= 20.45 cm³, Vs= 20 cm³, Ma= 0.04M . But molar mass of Na₂CO₃ = 106. So, concentration (g/dm³) = 0.02045 × 106 = 2.1677 g/dm³. Hence, The percentage purity of the sodium carbonate solid is 21.25%.