Question

If a bullet is fired with initial velocity of 4m/s the maximum range is

a)1600m
b)160m
c)16m
d)1.6m​

Answer 1

D 1.6 m

Step-by-step explanation:

Maximum range is obtained by firing at 45 degree angle

Vertical velocity is then 4 sin 45 = 2.83 m/s

gravity cause the velocity to be expressed as

v= 2.83 m/s - 9.81 t when it reaches its highest point...v = 0

0 = 2.83 - 9.81 t which shows t = .288 seconds

then it takes this same amount of time to fall back to the ground

for a total flight time of 2 * .288 = .577 seconds

For this .577 seconds it is traveling horizontally at the horizontal component 4 m/s cos 45 = 2.83 m/s

in .577 seconds it will travel downrange:

2.83 m/s * .577 s = 1.63 meters downrange