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Steps to finding the x-intercept and y-intercept of y=16x^2+32x

asked
User Beso
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1 Answer

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Answer:

y-intercept = (0,0)

x-intercepts (0,0), (-2, 0)

Explanation:

For y-intercept

If you think about a graph, when does the graph intercept/hit y. What is your value for x. Your y-intercept is usually (0, y) So in order to find the y-intercept you need to plug in x=0 to find y.

Equation:

y=16x²+32x substitute x=0

y=16(0)²+32(0)

y=0

y-intercept = (0,0)

For x-intercept

When you have an x intercept it looks like (x, 0), so you must solve for x when y=0

Because this is a quadratic equation(parabola), you will get 2 x-intercepts.

y=16x²+32x

0=16x²+32x > In order to solver for x, you must factor but in this case

you can take out the greatest common factor (GCF) =16x

0=16x(x +2) >Typically when you factor you get 2 parentheses and set

each parenthesis equal to 0, but instead we've pulled

an x on the outside. When there is an x outside you set

the outside equal to 0 as well as the parenthesis to

solve for x.

16x = 0 (x+2)=0

x=0 x= -2

x-intercepts (0,0), (-2, 0)

answered
User Bhuvan Bhatt
by
8.1k points

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