Answer:
Explanation:
You want two numbers such that ...
- first plus twice the second is 8
- twice the first plus the second is 34.
Setup
Let x and y represent the first and second numbers, respectively. Then the given relations can be written as the equations ...
x +2y = 8
2x +y = 34
Solution
Solving the first equation for x gives ...
x = 8 -2y
Using that in the second equation, we have ...
2(8 -2y) +y = 34
16 -3y = 34 . . . . . . eliminate parentheses
-18 = 3y . . . . . . . . add 3y-34
-6 = y . . . . . . . . divide by 3
x = 8 -2(-6) = 8 +12 = 20
The first number is 20, and the second number is -6.
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