Answer:
We can use the formula:
Q = m * c * ΔT
where Q is the heat released, m is the mass of the sample, c is the specific heat capacity, and ΔT is the temperature change.
We are given Q = 455 J, m = 45.0 g, and c = 2.44 J/g*°C.
Substituting these values into the formula, we get:
455 J = 45.0 g * 2.44 J/g*°C * ΔT
Simplifying and solving for ΔT, we get:
ΔT = 455 J / (45.0 g * 2.44 J/g*°C)
ΔT = 455 J / 109.8 J/°C
ΔT = 4.14 °C
Therefore, the temperature change of the ethanol sample will be 4.14 °C.