Question

A 8.5L balloon contains 3.5 moles of oxygen gas. If 2.3 moles are released from the balloon what is the final volume of the balloon?

Answer 1

12.9L

Step-by-step explanation:

V1 = 8.5L

P1 = 3.5

P2 = 2.3

V2 = ?

P1 V1 = P2 V2 ( Boyle's law )

3.5×8.5 = 2.3×V2

Divide both sides by 2.3

3.5×8.5/2.3 = 2.3×V2/2.3

V2 = 29.5/2.3

=12.9L