Answer:
50 calculators and 10 calendars.
Explanation:
Part A: Let x be the number of calculators and y be the number of calendars ordered. Then we have the following system of equations:
x + y = 60 (the total number of items ordered is 60)
12x + 10y = 700 (the total cost of the order is $700)
Part B: To solve this system by substitution, we can isolate x from the first equation and substitute it into the second equation. This gives us:
x = 60 - y
12(60 - y) + 10y = 700
Simplifying and solving for y, we get:
720 - 12y + 10y = 700
-2y = -20
y = 10
Therefore, the number of calendars ordered is 10. To find the number of calculators ordered, we can plug in y = 10 into the first equation and get:
x + 10 = 60
x = 50
Therefore, the number of calculators ordered is 50.