asked 2.9k views
2 votes
A spinner with nine equal-sized sections numbered one to nine is spun once. What is the probability that the spinner will land on a number that is not a multiple of three?

A. 1/3



B. 2/3



C. 7/9



D. 5’9

asked
User Select
by
8.0k points

2 Answers

5 votes

Answer:

B. 2/3

Explanation:

Probability is written like a fraction where on the bottom you have ALL the possibilities. There's 9 numbers on the spinner, so there's a total of 9 different ways for it to land.

9 ways total. That goes on the bottom of the fraction.

On top of the fraction you put however many number of ways the event in question can happen. That goes on top.

A multiple of three is 3, 6, 9. There are 3 ways the spinner can land on a multiple of three. So there are 6 ways to land on NOT a multiple of three (1, 2, 4, 5, 7, 8) 6 ways, so 6 goes on top.

6/9 is the answer. But always simplify fractions first, like you do.

6/9 simplifies to 2/3

The answer is

B. 2/3

answered
User Max Vollmer
by
7.9k points
5 votes

Answer:

2/3.

Explanation:

Total number of possible outcomes on one spin = 9.

Total of non multiples of 3:

1, 2, 4, 5,7 and 8

= 6

Answer is 6/9 = 2/3.

answered
User Reinaldo Chaves
by
8.9k points
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