Question

what is the concentration of a household ammonia cleaning solution if 49.90 ml of 0.5900 m HCl is required to neutralize 25.00 ml of the solution?

Answer 1

The balanced chemical equation for the neutralization reaction between ammonia (NH3) and hydrochloric acid (HCl) is:

NH3 + HCl → NH4Cl

From this equation, we can see that 1 mole of NH3 reacts with 1 mole of HCl to produce 1 mole of NH4Cl.

To find the concentration of the household ammonia cleaning solution, we can use the following formula:

M1V1 = M2V2

where M1 is the concentration of the HCl solution, V1 is the volume of the HCl solution used, M2 is the concentration of the ammonia solution, and V2 is the volume of the ammonia solution used.

Plugging in the given values, we get:

M1 = 0.5900 M

V1 = 49.90 mL = 0.04990 L

V2 = 25.00 mL = 0.02500 L

We can solve for M2:

M2 = (M1V1) / V2

M2 = (0.5900 M)(0.04990 L) / 0.02500 L

M2 = 1.17 M

Therefore, the concentration of the household ammonia cleaning solution is 1.17 M.

Step-by-step explanation: