Question

If i need to find x in y=a(b^x) what would the equation look like

Answer 1

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  `x=log_b(y/a)`

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Convert the equation in below steps to solve for x:

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  `y=ab^x`

Divide both sides by a:

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  `y/a=b^x`

Log both sides with base b:

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  `log_b(y/a)=log_bb^x`
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  `log_b(y/a)=x`

Here is the answer:

• 
  `x=log_b(y/a)`