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Answer: 6.11 L
Step-by-step explanation:
STP= 1atm, 273.15K
Molar mass of CO2=44.01g/mol so n= (12.0/44.01)
PV=nRT
V=(nRT)/P
V=((12.0/44.01)(0.0821)(273.15))/1
V=6.11L