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What is volume of 12.0 g of carbon dioxide at stp?

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Answer: 6.11 L

Step-by-step explanation:

STP= 1atm, 273.15K

Molar mass of CO2=44.01g/mol so n= (12.0/44.01)

PV=nRT

V=(nRT)/P

V=((12.0/44.01)(0.0821)(273.15))/1

V=6.11L

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User Djhurio
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