Question

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The reaction below generated 11.6 g Fe2S3 instead of the expected 16.8g. What is the percent yield?
2FeBr3 + 3N12S--> Fe2S3 + 6NaBr
A.) 69.0%
B.) 1.44%
C.) 5.2%
D.) 0.69%

Answer 1

Answer: A 69.0%

Step-by-step explanation:

divide the actual yield by the theoretical yield to get the %yield

11.6/16.8= 0.6904 or 69.0%