y = 1
5/y+3 + y/y-2 = 5/y+3 * y/y-2
5(y-2) + y(y+3) = 5y^2/(y+3)(y-2)
5y-10 + y^2 + 3y = 5y^2/(y^2-5y+6)
y^2 + 8y - 10 = 0
(y-1)(y+10) = 0
y = 1 or y = -10
However, y = -10 is not a valid solution since it makes the denominator of the original expression equal to 0.
Therefore, the only solution is y = 1.