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A 16 kg box is moving to the right while being pulled with a rope as shown in the picture. Force Tension is 150 N and = 40°. The coefficient of static friction µS = 0.6 and the coefficient of kinetic friction µK = 0.5. The acceleration in the y direction is 0 m/s/s

What is the magnitude of Force Normal?
What is the magnitude of Force Friction?
What is the acceleration rate of the box in the x direction?

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User Gishara
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Answer:

Step-by-step explanation:

Without the picture mentioned in the question, it's difficult to provide an accurate solution. However, here are some steps to solve the problem:

1. Draw a free-body diagram for the box, indicating all the forces acting on it. The forces include tension force, weight, normal force, and frictional force.

2. Calculate the weight of the box, which is given by the formula W = mg, where m is the mass of the box (16 kg) and g is the acceleration due to gravity (9.8 m/s^2). Therefore, W = 156.8 N.

3. Calculate the force normal, which is the force exerted by the surface on the box perpendicular to the surface. It can be calculated using the formula Fn = Wcosθ, where θ is the angle between the weight vector and the vertical axis. Since the acceleration in the y direction is 0, the box is not moving up or down. Therefore, the force normal is equal in magnitude and opposite in direction to the weight of the box, which is 156.8 N.

4. Calculate the force friction, which is the force exerted by the surface on the box in the opposite direction of its motion. If the box is not moving, then the frictional force is equal in magnitude and opposite in direction to the applied force. Therefore, the force friction is 150 N.

5. Calculate the acceleration rate of the box in the x direction, which can be determined using the formula Fnet = ma, where Fnet is the net force acting on the box in the x direction, m is the mass of the box, and a is the acceleration rate in the x direction. The net force in the x direction is given by the formula Fnet,x = Tcosθ - Ffriction - µSWsinθ, where T is the tension force, µS is the coefficient of static friction, and Wsinθ is the component of the weight vector parallel to the surface. If the box is moving, then the force of friction is kinetic friction, and the coefficient of kinetic friction µK is used instead of µS. The acceleration rate in the x direction can be determined by dividing the net force by the mass of the box, or a = Fnet,x/m.

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User Burktelefon
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