Question

There are two spinners. The first spinner has three same-sized sectors labeled 1, 2, and 3. The second spinner has four same-sized sectors labeled 3, 4, 5, and 6. The spinners are spun once. How many outcomes do not show an odd number on the first spinner and show a 3 on the second spinner?

Answer 1

The first spinner has a 1/3 chance of not showing an odd number, and the second spinner has a 1/4 chance of showing a 3. The probability of both events happening is:

1/3 x 1/4 = 1/12

Therefore, there is a 1/12 chance of an outcome showing a 3 on the second spinner and not showing an odd number on the first spinner. Since there are a total of 3 x 4 = 12 possible outcomes, the number of outcomes that meet the criteria is:

12 x 1/12 = 1

So there is only one outcome that meets the criteria.