o find the coordinates of the gates in the third quadrant, we need to find the points where the circle and the line intersect in the third quadrant.
Substituting y = 2x into x² + y² - 4x = 9, we get:
x² + (2x)² - 4x = 9
5x² - 4x - 9 = 0
Using the quadratic formula, we find:
x = (-(-4) ± √((-4)² - 4(5)(-9))) / (2(5))
x = (4 ± √136) / 10
We can discard the positive root since it is in the first quadrant. The negative root corresponds to the x-coordinate of the point of intersection in the third quadrant:
x = (4 - √136) / 10 ≈ -0.433
Substituting this value into y = 2x, we get:
y = 2(-0.433) ≈ -0.866
Therefore, the ordered pair that represents the location of the gates in the third quadrant is (-0.433, -0.866).