Question

The circle below is centered at the point (-3, 4) and has a radius of length 3.

What is its equation?
-10
-5
5

Answer 1

equation of a circle: (x-a)²+(y-b)²=r²

(x-(-3))²+(y-4)²=3²

(x+3)²+(y-4)²= 9

(x+6x+9)+(y-8y+16) =9

x+6x+9+y-8y+16=9

x+y+6x-8y+9+16-9=0

x+y+6x-8y+16 =0

Answer 2

C. (x + 3)² + (y - 4)² = 9

Explanation:

The equation for a circle is r² = (x - a)² + (y - b)² where "r" is the radius and (a, b) is the center.

We are given that (-3, 4) is the center and the radius is 3, so that means a = -3, b = 4, and r = 3. Insert the values to their respective places in the equation:

3² = (x - (-3))² + (y - 4)²

9 = (x + 3)² + (y - 4)²