Answer:
Approx 67.24%
Step-by-step explanation: If the Atlanta Hawks' free-throw percentage is 82%, the probability that a player will make one free throw is 0.82.
To find the probability that a player will make two free throws in a row, we can use the multiplication rule of probability which states that the probability of two independent events occurring together is the product of their individual probabilities.
Therefore, the probability of a player making two free throws in a row can be calculated as follows:
P(making two free throws in a row) = P(making first free throw) x P(making second free throw)
P(making two free throws in a row) = 0.82 x 0.82
P(making two free throws in a row) = 0.6724 or 67.24%
Therefore, the probability that a player for the Atlanta Hawks will make two free shots in a row is approximately 67.24%