asked 67.2k views
1 vote
What is x^2+y^2-16x+20y-5=0 in standard form

asked
User Afsantos
by
8.9k points

1 Answer

1 vote

Answer:

(x - 8)^2 + (y + 10)^2 = 169

Explanation:

you need to do completing the square

x^2 + y^2 -16x + 20y - 5 = 0

(x)^2 - 2(8)(x) + (y)^2 + 2(10)(y) - 5 = 0

(x)^2 + 2(-8)(x) + (-8)^2 - (-8)^2 + (y)^2 + 2(10)(y) + (10)^2 - (10)^2 - 5 = 0

[(x)^2 + 2(-8)(x) + (-8)^2] + [(y)^2 + 2(10)(y) + (10)^2] - (10)^2 - (-8)^2 - 5 = 0

### (a)^2 + 2(a)(b) + (b)^2 = (a + b)^2 ###

(x - 8)^2 + (y + 10)^2 -100 - 64 - 5 = 0

(x - 8)^2 + (y + 10)^2 -169 = 0

(x - 8)^2 + (y + 10)^2 = 169

answered
User Kunjan Thadani
by
8.2k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.