Question

What is the mass of 6. 02 x 10^22 molecules of fluorine gas at stop

Answer 1

3.7996 g

Step-by-step explanation:

From the number of molecules we can find the number of moles of Fluorine gas (F2) and multiply by Fluorine Gas' molecular weight. Fluorine gas is F2,

F = 18.998g/mol.

F2 (g) = 18.998*2 =37.996g F2(g)/mol

1 mol = 6.02 x 10^23 molecules

`(6.02*10^(22) molecules)/(6.02*10^(23)molecules / mole )\\\\ = 0.1 mole`

0.1 mol x 37.996g F2 (g) / mol

3.7996 g F2