asked 45.1k views
2 votes
Write the factored form of the polynomial function with real coefficients, a lead coefficient of 1, and zeros of -1,-3,3,1

asked
User Kerryann
by
8.5k points

1 Answer

0 votes

Answer:

To find the factored form of the polynomial function, we start by using the zeros to write out the factors of the polynomial. If the zeros are a, b, c, d, then the factors are (x-a), (x-b), (x-c), and (x-d).

In this case, the zeros are -1, -3, 3, and 1, so the factors are (x+1), (x+3), (x-3), and (x-1). Multiplying these factors together gives the polynomial function:

f(x) = (x+1)(x+3)(x-3)(x-1)

To simplify this expression, we can use the distributive property to expand the factors:

f(x) = (x+1)(x^2 - 9)(x-1)

Next, we can multiply the remaining factors using the distributive property and combining like terms:

f(x) = (x^3 - 8x - 9)(x-1)

Finally, we can use the distributive property again to expand the remaining factor:

f(x) = x^4 - 9x^2 + 8x + 9x^3 - 8x - 9

Simplifying this expression gives the factored form of the polynomial function:

f(x) = (x+1)(x+3)(x-3)(x-1) = x^4 - 9x^2 + 8x - 9x^3 - 8x - 9.

answered
User Bill Chan
by
8.1k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.