Question

Solve each of the following systems of equations. Find all solutions.

(a)
x+y=-1
3x=4-3y

(b)
3x-4y+2=0
10-10y=10y-15x

Answer 1

Explanation:

(a)

x + y = -1

3x = 4 - 3y

from 1st equation we can write x = -1 - y and put this x in the 2nd equation

3(-1 -y) = 4 -3y

-3 -3y = 4 -3y

now here y is getting cancel so that means this two equation has no common solution.

(b)

3x - 4y +2 = 0

10 -10y = 10y -15x

from 1st equation we can write x = (4y - 2)/3 and put this x in the 2nd equation

10 = 10y +10y -15((4y - 2)/3)

2 = 2y +2y - 3((4y -2)/3)

2 = 4y - (4y - 2)

again here 4y and 4y getting cancel so both the equation has no common solution.