Okay, here are the steps to find the probability that Josie will be placed in an A group with an even number:
1) There are 2 possible letters (A or B) and 6 possible numbers (1-6) for the groups. So there are 2 * 6 = 12 possible groups total.
2) Half of the groups (6 groups) will be A groups.
3) Half of the groups (6 groups) will have an even number (2, 4, 6)
4) So there are 6 * 6 / 12 = 1/2 = 0.5 probability that a randomly selected group will be an A group with an even number.
5) Therefore, the probability that Josie will be placed in an A group with an even number is 0.5.
Work shown:
Total groups: 12
A groups: 6
Even number groups: 6
Probability A group with even number: 6 * 6 / 12 = 1/2 = 0.5
Prob Josie in A even group: 0.5
0.5
Let me know if you have any other questions!