Question

an object located 32.0 cm in front of a lens forms an image on a screen 8.00 cm behind the lens. (a) find the focal length of the lens. (b) determine the magnification. (c) is the lens converging or diverging?

Answer 1

The answer to your problem is:

A. 6.4

B. -0.25

C. converging

Step-by-step explanation:

[ /Part A/ ]

We know that;

`(1)/(32) + (1)/(8) + (1)/(f)`

Then equals

6.4
`Which`
`is`
`our`
`answer`

[ /Part B/ ]

We can solve the problem which equals to:

$$ M = -
`\frac {q}{p}` = -
`\frac {8}{32}`

Solve: -0.25

[ /Part C/ ]

In the problem we now that ‘ f ‘ is more less than ‘ o ‘ is converging.

Shown, since ‘ f ‘ > ‘ 0 ‘ lens is converging

Thus the answer to your problem is:

Part A. 6.4

Part B. -0.25

Part C. converging