Question

To make a 4 cup pot of green tea, one must heat the water to the boiling point at standard pressure. If the pot contains 680 grams of water, and the temperature at the tap is 20.0°C, how much heat must be absorbed by the water?

Answer 1

To calculate the amount of heat that must be absorbed by the water, we can use the specific heat capacity of water and the formula:

Q = m * c * deltaT

where Q is the amount of heat absorbed by the water, m is the mass of the water, c is the specific heat capacity of water, and deltaT is the change in temperature.

The specific heat capacity of water is 4.184 J/g°C.

First, we need to calculate the change in temperature of the water. We know that the water needs to be heated to the boiling point, which is 100°C at standard pressure. Therefore, deltaT = 100°C - 20.0°C = 80.0°C.

Next, we can plug in the values we know:

Q = m * c * deltaT
Q = 680 g * 4.184 J/g°C * 80.0°C
Q = 227,584.0 J

Therefore, the amount of heat that must be absorbed by the water to make a 4 cup pot of green tea is 227,584.0 J.