Question

find the volume of 0.170 m sulfuric acid necessary to react completely with 77.7 g sodium hydroxide. express your answer with the appropriate units.

Answer 1

5.7dm³

Step-by-step explanation:

H2SO4 + 2NAOH =>>> NA2SO4 +2H20

77.7g of NaOH divided by 40g/mol = 1.9425moles

if 1 moles of H2SO4 reacts with 2 moles NaOH

then x will be formed when 1.9425 moles of NaOH

x = 0.97125 moles of H2SO4

n = concentration × volume

0.97125 = 0.17M × volume

volume = 5.7dm³