asked 72.2k views
0 votes
How many atoms are in 1.75 moles of CHCl3?

1 Answer

5 votes

Answer: there are 5.263 x 10^24 atoms in 1.75 moles of CHCl3.

Explanation: To calculate the number of atoms in 1.75 moles of CHCl3 (chloroform), we first need to determine the molecular formula of CHCl3 and then use Avogadro's number to convert the number of moles to the number of atoms.

The molecular formula of CHCl3 is:

Carbon (C) - 1

Hydrogen (H) - 1

Chlorine (Cl) - 3

So, the total number of atoms in CHCl3 is:

1 (C) + 1 (H) + 3 (Cl) = 5

One mole of any substance contains 6.022 x 10^23 particles, which is known as Avogadro's number. Therefore, to calculate the number of atoms in 1.75 moles of CHCl3, we need to multiply 1.75 by Avogadro's number and then by the total number of atoms in CHCl3:

1.75 mol CHCl3 x 6.022 x 10^23 molecules/mol x 5 atoms/molecule = 5.263 x 10^24 atoms of CHCl3

answered
User Aaron Krajeski
by
8.3k points

Related questions

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.