To solve for x and y, we can use substitution.
From the second equation, we have y = 2 - x.
Substituting this into the first equation, we get:
Sax + b(2 - x) = 0
Expanding this equation, we get:
Sax + 2b - bx = 0
Rearranging the terms, we get:
x(Sa - b) = 2b
Dividing both sides by (Sa - b), we get:
x = 2b/(Sa - b)
Substituting this value of x into the second equation, we get:
2b/(Sa - b) + y = 2
Substituting y = 2 - x, we get:
2b/(Sa - b) + (2 - 2b/(Sa - b)) = 2
Simplifying this equation, we get:
4b/(Sa - b) = 2
Multiplying both sides by (Sa - b)/2, we get:
2b = (Sa - b)
Simplifying this equation, we get:
b = a/2
Substituting this value of b into the equation for x, we get:
x = 2b/(Sa - b) = 2(a/2)/(Sa - a/2) = a/(2S - 1)
Substituting these values of x and y into the given point (x, y) = (a + b), we get:
(a/(2S - 1), 2 - a/(2S - 1)) = (a + a/2, a/2)
Therefore, the solution is:
x = a/(2S - 1) and y = 2 - a/(2S - 1).