Question

How many grams of sodium chloride are there in 550 mL of a 1.90 M aqueous solution of sodium chloride

Answer 1

Step-by-step explanation:

n=cv

n=1.90×550

1045÷1000

n=1.045

n=m/mm

cross multiple

n×mm=m

1.045×816.5=m

853.2425=m