Question

An object is undergoing SHM with amplitude AA . For what values of the displacement is the kinetic energy equal to 1/31/3 of the total mechanical energy

Answer 1

Answer:
`\sqrt {(2)/(3)}\,A`

Explanation:

`v^2=\omega^2(A^2-x^2)\\KE_(\rm max) = \frac 12 m \omega^2A^2\\\frac 13\cdot \frac 12 m \omega^2A^2= \frac 12 m v^2=\omega^2(A^2-x^2)\Rightarrow x=√(\frac 23)\,A`