Question

I have 38 L of gas at a pressure of 0.50 atm and a temperature of 325 K. What is the final volume if I raise the pressure to 1.5 atm and decrease the temperature to 220 K

Answer 1

To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas:

P1V1/T1 = P2V2/T2

where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.

We can start by plugging in the given values:

P1 = 0.50 atm

V1 = 38 L

T1 = 325 K

P2 = 1.5 atm

T2 = 220 K

Step-by-step explanation:

Answer 2

To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas:

P1V1/T1 = P2V2/T2

where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.

We can start by plugging in the given values:

P1 = 0.50 atm
V1 = 38 L
T1 = 325 K
P2 = 1.5 atm
T2 = 220 K

We can solve for V2:

P1V1/T1 = P2V2/T2

(0.50 atm)(38 L)/(325 K) = (1.5 atm)(V2)/(220 K)

Simplifying, we get:

V2 = (0.50 atm)(38 L)(220 K)/(1.5 atm)(325 K)

V2 = 12.7 L

Therefore, the final volume is 12.7 L.