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5 votes
A rocket is launched from the top of a 50 foot cliff with an initial velocity of 100 feet per second. The​ height, h, of the rocket after t seconds is given by the equation h=-16t²+100t+50. How long after the rocket is launched will it be 10 feet from the​ ground?

1 Answer

7 votes

Answer:

d

Explanation:

answered
User Manthan
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