Question

Pat and Jeff walk to dock at 2 mph, jumped into the boat, and motored to Dillon at 8mph. If the total distance is 13 miles and trip took 11/4 in all, how far did boat go?

Answer 1

Let's start by using the formula:

distance = rate x time

Let d be the distance the boat traveled, in miles.

The time it took Pat and Jeff to walk to the dock is the same as the time it took them to motor to Dillon, so we can write:

d/8 = (13 - d)/2

Simplifying this equation, we get:

d = 8(13 - d)/2

d = 52 - 4d

5d = 52

d = 10.4

Therefore, the boat traveled a distance of 10.4 miles.